Using python_requires to require Python 2.7 or 3.2+

Question

How do I use python_requires classifier in setup.py to require Python 2.7.* or 3.2+?

I have tried many configurations, including this one: ~=2.7,==3,!=3.0,!=3.1,<4 but none have worked

wim · Accepted Answer · 2021-05-12T01:33:56.967

45

This argument for setuptools uses the PEP440 version specifiers spec, so you can ask for:

python_requires='>=2.7,!=3.0.*,!=3.1.*'

The commas , are equivalent to logical and operator.

Note that the metadata generated is only respected by pip>=9.0.0 (Nov 2016).

edited May 12 '21 at 01:33

answered Jun 20 '17 at 18:28

wim

9

See also the relevant [setuptools doc](https://setuptools.readthedocs.io/en/latest/setuptools.html?highlight=python_requires#new-and-changed-setup-keywords) and [PEP 345](https://www.python.org/dev/peps/pep-0345/). – Asclepius Jun 23 '17 at 00:53
2

See also: https://packaging.python.org/guides/distributing-packages-using-setuptools/#python-requires – 0 _ Feb 04 '19 at 21:46
Sadly, following the links shows that the "," is treated as `and`, so something like "`==2.7, >=3.9`" will never work. – Aaron D. Marasco May 11 '21 at 22:11

1 Answers1