java.net.MalformedURLException in android while accessing asp.net Web API

Question

I've seen this question, it's not my case, since I don't have backslashes in my url,
I have simple URL like, https://url.com/login

My Code,

import android.content.Intent;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.v7.app.AppCompatActivity;
import android.view.View;
import android.widget.EditText;
import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.URL;

public class LoginActivity extends AppCompatActivity {

    URL url = new URL("https://url.net/login/");


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_login);

        FloatingActionButton btn = (FloatingActionButton) findViewById(R.id.submitbtn);
        EditText edtxt = (EditText) findViewById(R.id.usernm);
        EditText edtxt2 = (EditText) findViewById(R.id.usrpwd);

        btn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                Intent i = new Intent(getApplicationContext(),HomeActivity.class);
                startActivity(i);
            }
        });

        HttpURLConnection urlConnection = null;
        try {
            urlConnection = (HttpURLConnection) url.openConnection();
        } catch (IOException e) {
            e.printStackTrace();
        }
        try {
            InputStream in = new BufferedInputStream(urlConnection.getInputStream());
            readStream(in);
        } finally {
            urlConnection.disconnect();
        }
    }
}

Screen shot:

When I hover on new URL();, I get error as:

Unhandled Exception: java.net.MalformedURLException

That's why I'm getting another error at line,

InputStream in = new BufferedInputStream(urlConnection.getInputStream());
readStream(in);

in stack Trace I'm getting error as,

Error:(48, 13) error: cannot find symbol method readStream(InputStream)

image is for error, That's the line of error and I'm getting error as `Error:(48, 13) error: cannot find symbol method readStream(InputStream)` — Nirav Madariya, Jun 14 '17 at 14:32

score 2 · Accepted Answer · answered Jun 14 '17 at 14:34

When I hover on new URL();, I get error as:

The URL() constructor throws java.net.MalformedURLException. You need to wrap that constructor call in a try/catch block.

That's why I'm getting another error at line,

That is because getInputStream() also throws checked exceptions. You need to wrap that code in a try/catch block.

That's the line of error and I'm getting error as Error:(48, 13) error: cannot find symbol method readStream(InputStream)

That is because you did not implement a method named readStream() on this class.

All of this is covered in any decent book or course on Java programming.

Eventually, once you get past these compile errors, your code will crash at runtime with a NetworkOnMainThreadException, as you cannot perform network I/O on the main application thread. You will need to move this HTTP code to a background thread, either one that you create yourself or by using an HTTP client API that can handle it for you (e.g., OkHttp).

java.net.MalformedURLException in android while accessing asp.net Web API

1 Answers1