yii2 conditional validation on server side

Question

I have one form that form have below fields

i)Book ii)Amount

Controller action:

public function actionBook()
{   
    $model = new Book();
    if ($model->load(Yii::$app->request->post()) && $model->validate()){ 
        print_r($model);exit;
        return $this->redirect('/Book');
    }
    $model->getBook();
    return $this->render('BookForm', ['model' => $model]);
}

Whenever this page will load i will call one model function by default, the function is getBook()

Model:

public book;
public amount;
public showAmountField;

public function rules()
{   
 return [
  [['book'], 'required'],
  ['amount', 'required', 'when' => function($model) {
        return $model->showAmountField == true;
    }],
 ];
}

public function getBook()
{
 if(some condition here){
  $this->showAmountField = true;
 }
}

so whenever the showAmountField is true at the time the amount field is required, otherwise it will not required, here all are working fine and the client side validation also working fine, but when i change amount field id using console(f12) at the time the server side validation not working and form is simply submit with the amount field is empty, so what is wrong here. Please explain anyone.

UPDATE

View

<?php
 use yii\helpers\Html;
 use yii\bootstrap\ActiveForm;
 $this->params['breadcrumb'] = $model->breadCrumbs;
?>

<?php $form = ActiveForm::begin([
  'id' => 'book-form',  
  'options' => ['class' => 'form-horizontal'],
  ]); 
 ?>
<?= $form->field($model, 'book')->textInput()->label("Book"); ?>
<?php if($model->showAmountField): ?>      
  <?= $form->field($model, 'amount')->textInput()->label("Amount"); ?>
<?php endif; ?>  
<?= $form->errorSummary($model, ['header' => '']); ?>
<?php ActiveForm::end(); ?>

you have to render into same form page in order to see your validation error, moreover you stop the script by adding "exit". — Rajesh Pradhan, Jun 13 '17 at 11:35

score 2 · Answer 1 · answered Jun 13 '17 at 10:59

2

Validation occurs on the field ID, if you change it through the console, the model does not understand that it needs to validate

answered Jun 13 '17 at 10:59

Sersh

308
1
11

Show your view file – Sersh Jun 13 '17 at 11:05
@VishvaG, he just told you. By changing the element using the console the server doesn't pair it to the model. Try to echo values, step by step, to understand what happens. – walther Jun 13 '17 at 11:22
yes i understand obviously client side validation not work,but i dont know why server side validation not work, it's happen only on conditional validation not normal required validation – Vishva G Jun 13 '17 at 11:28

score 1 · Accepted Answer · answered Jun 13 '17 at 13:14

$model = new Book();
if ($model->load(Yii::$app->request->post()) && $model->validate()){ 
    print_r($model);exit;
    return $this->redirect('/Book');
}
$model->getBook();

here you are initialising the $model->getBook(); after the if block so the model gets overridden in post request with new instance and hence server side validations fails for when condition.

    $model = new Book();
    $model->getBook();
    if ($model->load(Yii::$app->request->post()) && $model->validate()){ 
        print_r($model);exit;
        return $this->redirect('/Book');
    }

it should be before post load

i want again reinitialize model with that function so that only put below, anyway thank you for your answer. i will do alternative for that. — Vishva G, Jun 16 '17 at 07:24

yii2 conditional validation on server side

2 Answers2