I can't find a way to convert my QList<T> to a QVariant.
There's a constructor QVariant(const QList<QVariant> &val), but no constructor for QList<T> , is it possible to convert directly a QList<T> ?
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Evans Belloeil
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Assume that your T typename is included in QVariant union types (otherwise you cannot). why you don't convert every T object in QVariant, put all this converted in QList
and finally convert it to QVariant ? – Mohamed Hamzaoui Jun 08 '17 at 13:00 -
@requinham I was hoping there was something more simple ... – Evans Belloeil Jun 08 '17 at 13:03
1 Answers
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Example
QList<int> ints{1,2,3};
QVariant var = QVariant::fromValue<QList<int>>(ints);
olya
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Qt Note: If you are working with custom types, you should use the Q_DECLARE_METATYPE() macro to register your custom type. – Mohamed Hamzaoui Jun 08 '17 at 13:09