Cut a longer word/string in smaller chunks for fitting a field

Question

I want to fill a field with a string of many words. When I have huge words I need a to split the word. If my word is longer than 10 letters I need a space at position 5 of this word.

How do I get the new "myString" with shorter words?

    static void Main(string[] args)
    {
        var myString = "This is my string with some loooooooooooooong words. Please devide meeeeeeeeeeeeeeeeeeeeeeeee";
        var myStringSplit = myString.Split();
        var query = myStringSplit.Where(x => x.Length > 10).ToList();
        foreach (var item in query)
        {
            item.Insert(5, " ");
        }
    }

Edit: My expected result: myString = "This is my strin g with some loooo ooooo ooooo ng words. Pleas e devid e meeee eeeee eeeee eeeee eeeee e";

You are showing us your code...what about it is not working? Why did you show us your code? — rory.ap, Jun 07 '17 at 11:35
Still unclear what you want to do... For example in the string given, what result you want? — xanatos, Jun 07 '17 at 11:35
@kame please add what you expect to get as a result. It's not clear from your question what your problem is. — Samvel Petrosov, Jun 07 '17 at 11:38

Samvel Petrosov · Accepted Answer · 2017-06-07T12:32:49.583

2

Here is example how you can get your result:

public static void Main(string[] args)
{
    var myString = "This is my string with some loooooooooooooong words. Please devide meeeeeeeeeeeeeeeeeeeeeeeee";
    string[] myStringSplit = myString.Split();
    for (int i =0;i<myStringSplit.Length;i++)
    {
        if(myStringSplit[i].Length>5)
            myStringSplit[i] = Regex.Replace(myStringSplit[i], ".{5}(?=.)", "$0 ");
    }
    var resultString = myStringSplit.Aggregate((x,y)=> x+" "+y);
    Console.WriteLine(resultString);
}

The output will be the following:

This is my strin g with some loooo ooooo ooooo ng words . Pleas e devid e meeee eeeee eeeee eeeee eeeee e

edited Jun 07 '17 at 12:32

answered Jun 07 '17 at 11:50

Samvel Petrosov

7,580
2
22
46

The `Regex` should be `Regex.Replace(myStringSplit[i], ".{5}(?=.)", "$0 ");` or `".{5}(?!$)"` (test with a string of 10 characters, with your regex it is `12345 67890 ` with an extra space at the end. And instead of `Aggregate` you could use `string.Join`: `string.Join(" ", myStringSplit)` – xanatos Jun 07 '17 at 12:13

Lifewithsun · Answer 2 · 2017-06-07T11:45:02.907

0

Try this might be helpful

static void Main(string[] args)
        {
            var myString = "This is my string with some loooooooooooooong words. Please devide meeeeeeeeeeeeeeeeeeeeeeeee";
            var myStringSplit = myString.Split();
            var query = myStringSplit.Where(x => x.Length > 10).ToList();
            foreach (var item in query)
            {
                string outString = Regex.Replace(item, ".{5}", "$0 ");
            }
        }

This will separates the string after each five words..

Edited

edited Jun 07 '17 at 11:45

answered Jun 07 '17 at 11:41

Lifewithsun

968
14
34

But I just want to split words with a size longer than 10 characters. – kame Jun 07 '17 at 11:44
Edited as per your requirement – Lifewithsun Jun 07 '17 at 11:47
I just want to split the word which is longer than 10 characters. Therefore I have to take the long words first. – kame Jun 07 '17 at 11:48
Variable query will holds the values which are longer than the 10 character. Then we are looping the same and adding space after 5 character. – Lifewithsun Jun 07 '17 at 11:49

score 0 · Answer 3 · answered Jun 07 '17 at 11:44

static void Main(string[] args)
{
    var myString = "This is my string with some loooooooooooooong words. Please devide meeeeeeeeeeeeeeeeeeeeeeeee";
    var newString = string.Empty;
    var myStringSplit = myString.Split();
    var query = myStringSplit.Where(x => x.Length > 10).ToList();
    foreach (var item in myStringSplit)
    {
        if(item.Length > 10)
        {
            var itemToSplit = item;
            itemToSplit.Insert(5, " ");
            newString += itemToSplit;
        }
        else
        {
           newString += item;
        }
    }
}

It should be something like this. The reason your attempt is not working is because you are not allowed to edit the item in the foreach loop. More info on the foreach loop

Cut a longer word/string in smaller chunks for fitting a field

3 Answers3