I have cell array that is as follow:
S{1} = [10,20,30,40,50];
S{2} = [10,20,40,50];
S{3} = [10,50,510];
S{4} = [10,20,70,40,60];
S{5} = [20,40];
and, i need to find rows of cell that are subitem of:
[10,20,30,40,50,60]
for above example result is :
1,2,5
because row 1 and row 2 and and row 5 only have subitems of [10,20,30,40,50,60] .
in my work cell array is big. and i need a fast code.
Let
S{1} = [10,20,30,40,50];
S{2} = [10,20,40,50];
S{3} = [10,50,510];
S{4} = [10,20,70,40,60];
S{5} = [20,40]; % data
t = [10,20,30,40,50,60]; % target values
Then, you can apply ismember and all to each cell's contents via cellfun. The result is a logical vector, from which you obtain the desired indices with find:
result = find(cellfun(@(x) all(ismember(x, t)), S));
An alternative (I don't know which one will be faster in your case) is to replace ismember by computing all pairwise comparisons with bsxfun and then applying any:
result = find(cellfun(@(x) all(any(bsxfun(@eq, t(:), x(:).'), 1)), S));
