Notice that the feasible region here is non-convex -- if we have one feasible solution with x_1 = 0.01 and another with x_1 = 0.05 then any proper convex combination of these two solutions will be infeasible. Because of this, it is provably impossible to reformulate this problem to a standard quadratic program using only continuous variables.
Instead, you will need to resort to using binary variables. For instance, we could introduce binary variables y_i (one per x_i variable) and reformulate the problem as:
Minimize (1/2)X^TQX + C^TX
Subject to -0.01 + 0.06y_i <= x_i <= 0.01 + 0.19y_i, for any x_i in X
y_i binary
Note that now for any variable with y_i = 0 you have -0.01 <= x_i <= 0.01, and for any variable with y_i = 1 you have 0.05 <= x_i <= 0.20.