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i want to know whether their is any way in ios 4.0 and onwards to make a call from application without exiting the application.

I have worked on this and got to know that their is not any way till iOS 3.1. So I want to know is iOS 4 supports it or not. Need Some other solution than that of

UIApplication application] openURL:[NSURL URLWithString:@"tel://8005551212"]];

Dipti Y W
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1 Answers1

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You can use 

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt://8005551212"]];

for iOS 4.x it works.

Charles Samuel D'Monte
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Rostyslav Druzhchenko
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  • I am using same but it exits app. We have to reopen it. As iphone 4 supports multitasking App starts from the point where it exits. – Dipti Y W Jul 25 '11 at 07:21