Double recognising as Int in JSONObject

Question

I'm trying to add an double value to an JSONObject, its automatically recognising as int(code below). After jsonObject.put the unitCost is converted to integer automatically to {"unitCost":100} rather than {"unitCost":100.0}. Please help i need to keep it as double.Thanks

Double unitCost = 100.0D;

JSONObject jsonObject = new JSONObject();

jsonObject.put("unitCost", unitCost);

check with different value like as 987.56 – chetan mekha May 16 '17 at 07:42 — chetan mekha, May 16 '17 at 07:42
String is safe for your requirement – IntelliJ Amiya May 17 '17 at 06:43 — IntelliJ Amiya, May 17 '17 at 06:43

IntelliJ Amiya · Answer 1 · 2017-05-16T07:53:09.033

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It will be better if you use String

Strings are constant;

String unitCost = "100.0";
JSONObject jsonObject = new JSONObject();
jsonObject.put("unitCost", unitCost);

edited May 16 '17 at 07:53

answered May 16 '17 at 07:36

IntelliJ Amiya

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score 0 · Answer 2 · answered May 16 '17 at 07:33

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Its not converting double into int. If the first decimal digit is 0, it won't be visible, Change it to 100.1 , you will be able to see the double value.

answered May 16 '17 at 07:33

Dishonered

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i dont want to change it to 100.1. Is there any other way? – Vishruth V Athrey May 16 '17 at 07:35
I agree with you @Sushobh. – Nitin Patel May 16 '17 at 07:35
@VishruthVAthrey Then use String.. – Nitin Patel May 16 '17 at 07:35
There is actually no problem with 100.0 , the 0 is simply invisible. – Dishonered May 16 '17 at 07:37
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In statistics/engineering, "100" and "100.0" could mean two different things, as the later is a more accurate measurement. However, when using the JSON API, the zero after the comma will be discarded. If you really need to display the ".0", your only choice is representing it as a String. – Danilo M. Oliveira May 16 '17 at 07:51

Double recognising as Int in JSONObject

2 Answers2