iOS XCTestCase to launch, perform some actions, kill the app and re-launch app

Question

I have to automate following scenario using swift and XCTestCase on iOS simulator.

Step1: Launch the app
Step2: Performa some actions on the app
Step3: Kill the app
Step4: Re-launch the app and check if the actions performed are persistent

I found in one of our questions to use the below snippet.

    XCUIDevice.shared().press(XCUIDeviceButton.home)
    sleep(60)
    XCUIDevice.shared().siriService.activate(voiceRecognitionText: "Open {appName}")

It did not work for me, can some one please suggest any different approach.

thanks,

You are doing unit tests, right? If so, can you switch over to Xcode *UI tests* for this specific test? — Paulo Mattos, May 10 '17 at 02:57

score 3 · Answer 1 · edited May 10 '17 at 13:14

3

To launch or re-launch use launch:

XCUIApplication().launch()

To terminate application use terminate(). But according to the documentation:

If the application is already running, this call will terminate the existing instance, to ensure a clean launch state for the newly launched instance.

Shortly. Your test could look like:

XCUIApplication().launch()
// some actions
XCUIApplication().launch()
// some action

edited May 10 '17 at 13:14

Paulo Mattos

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answered May 10 '17 at 11:42

Bartosz Janda

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Nice answer! But I believe this would only work if he is using UI tests (and not unit tests), right? – Paulo Mattos May 10 '17 at 13:15
1

Yes. This will only work with UI test. I doubt it could be done with unit tests. – Bartosz Janda May 10 '17 at 16:21

iOS XCTestCase to launch, perform some actions, kill the app and re-launch app

1 Answers1