NSArray* nameArr = [NSArray arrayWithObjects: @"Jill Valentine", @"Peter Griffin", @"Meg Griffin", @"Jack Lolwut",
@"Mike Roflcoptor", @"Cindy Woods", @"Jessica Windmill", @"Alexander The Great",
@"Sarah Peterson", @"Scott Scottland", @"Geoff Fanta", @"Amanda Pope", @"Michael Meyers",
@"Richard Biggus", @"Montey Python", @"Mike Wut", @"Fake Person", @"Chair",@"subbu",@"reddy",@"suresh",@"harish",@"naresh",@"giri",@"nani",
nil];
for (i=0; i<=nameArr.count i++)
{
NSMutableDictionary *dic=[NSMutableDictionary new];
[dic setObject:@"nameArr" forKey:@"name"];
}
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Ketan Parmar
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subbu
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what you want as result ? – Ketan Parmar May 08 '17 at 13:00
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2Try this `[dic setObject:nameArr forKey:@"name"];`. Dont need to use for loop. – RajeshKumar R May 08 '17 at 13:01
4 Answers
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You are creating NSMutableDictionary object each and every time.
You should declare that object out side of for loop.
Here is the code
NSMutableDictionary *dic=[NSMutableDictionary new];
for (i=0; i<=nameArr.count i++)
{
NSString *nameObj = nameArr[i];
[dic setObject:nameObj forKey:@"name"];
}
But clear the purpose as this code is not proper.
It states that you are compiling loop number of item array has, and you are adding same array to that dictionary on same key.

vivek bhoraniya
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I know...but what OP want here is more important so I have just correct his code. – vivek bhoraniya May 08 '17 at 13:08
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0
Try like this:
NSMutableDictionary *dic = @{ @"name" : nameArr}.mutableCopy;

NeverHopeless
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0
Try this :
If you want to add array .
NSMutableDictionary *dic = @{ @"name" : nameArr}. mutableCopy;
If you want to add array objects.
NSMutableDictionary *dic=[NSMutableDictionary new];
for (NSString *strname in nameArr) {
[dic setObject:strname forKey:@"name"]
}

KKRocks
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0
Currently you are adding nameArr as a string, in case you need to add array for a particular key try below:
NSMutableDictionary *nameDictionary = [NSMutableDictionary new];
[dic setObject:nameArr forKey:@"name"];
Hope this helps!

iYoung
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