How to covert Scala Seq to Java Enumeration

Question

I want to convert a scala Seq to Java java.util.Enumeration any tips?

What did you try or find already? For example, http://stackoverflow.com/a/5184386/2308683 — OneCricketeer, May 08 '17 at 12:06
can you give a few more details? it seems an odd use case. Maybe you have a List of Strings and you want to convert each to one of the possible Enumeration values? — pedrorijo91, May 08 '17 at 12:29
@pedrorijo91 `java.util.Enumeration` has nothing to do with enums. It's a pre-Java 1.2 version of `java.util.Iterator`. — sepp2k, May 08 '17 at 12:43
The issue is I'm using a library that needs an Enumeration as argument to functions. but I have a Set in Scala. The Solution was to use `asEnumeration(someSet)` in JavaConvertors. — Boynux, May 09 '17 at 09:23

score 1 · Accepted Answer · answered Oct 22 '17 at 08:25

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In case someone else is interested in the answer:

By importing scala.collection.JavaConversions I could use asJavaEnumeration[A](i: Iterator[A]): Enumeration[A] to do the job.

answered Oct 22 '17 at 08:25

Boynux

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Is there any way to combine 2 Enumeration of same class? – Mr Sindhu Dec 29 '21 at 13:21

score 0 · Answer 2 · edited May 23 '17 at 12:26

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Enumeration is basically an outdated thing. It is one of those concepts that were introduced with Java 1.0, but that nobody would / should be using any more nowadays.

In 2017, you use collections. In other words: if at all, you turn your Seq into a List. You can read about how to do that here.

edited May 23 '17 at 12:26

Community

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answered May 08 '17 at 12:07

GhostCat

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How to covert Scala Seq to Java Enumeration

2 Answers2