Pop to rootviewcontroler containing presented navigation as well

Asked May 04 '17 at 08:45

Active May 04 '17 at 09:10

Viewed 46 times

My app architecture is :

RootNavigationController
-(rootVC)> HomeVC
-(pushed)> SecondVC
-(presented)> SecondNavigationController
-(rootVC)> ThirdVC
-(pushed)> FourthVC.

Now there is an option of returning to HomeVC on FourthVC.

What I have tried:

  APPDELEGATE.window?.rootViewController = UIStoryboard.HomeNavigationViewController()

Problem : This way all VCs added on RootNavigationController are not deinitilized and memory leaked.

  self.dismiss(animated: true, completion: nil)
  (self.navigationController?.presentingViewController as? UINavigationController)?.viewControllers.removeAll()
 APPDELEGATE.window?.rootViewController = UIStoryboard.HomeNavigationViewController()

This way its working fine but what I need to know is there any better way of doing it.

edited May 04 '17 at 09:10

asked May 04 '17 at 08:45

ankit

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Try this one: `UIApplication.shared.windows.first?.rootViewController?.navigationController?.popToRootViewController(animated: true)` – Laffen May 04 '17 at 08:54
see this approach : http://stackoverflow.com/a/39831374/3901620 – KKRocks May 04 '17 at 09:00
try this also let navigationController = self.presentingViewController as? UINavigationController self.dismiss(animated: true) { let _ = navigationController?.popToRootViewController(animated: true) } – KKRocks May 04 '17 at 09:02
ok guys let me test it. – ankit May 04 '17 at 09:03
@Laffen your method suggestion doesn't work. – ankit May 04 '17 at 09:09
@KKRocks your suggestion equals to dismiss and it only removes presented VCs. – ankit May 04 '17 at 09:09
it is check first if present then dismiss it and then pop back to root . – KKRocks May 04 '17 at 09:10
yep I tried that – ankit May 04 '17 at 09:11

Pop to rootviewcontroler containing presented navigation as well

0 Answers0