2

I want to produce the following XML:

<Base>
    <Child>
        <Name>Joe</Name>
    </Child>
    <Child>
        <Name>Jack</Name>
    </Child>
</Base>

From the classes:

public class Base
{
    public List<Child> children;
    ...elided...
}

public class Child
{
    public string Name;
    ...elided...
}

Right now, it's creating:

<Base>
    <children>
        <Child>
            <Name>Joe</Name>
        </Child>
        <Child>
            <Name>Jack</Name>
        </Child>
    </children>
</Base>

How would I change to produce the desired output?

My current code:

XmlSerializer serializer = new XmlSerializer(base.GetType());
serializer.serialze(stringWriter, base);
return stringWriter.ToString();
Don Rhummy
  • 24,730
  • 42
  • 175
  • 330

3 Answers3

4

Use the XmlElementAttribute

public class Base
{
    [XmlElement(ElementName = "Child")]
    public List<Child> children;
}

... full example ...

using System.Collections.Generic;
using System.IO;
using System.Text;
using System.Xml.Serialization;

class Program
{
    static void Main()
    {
        var xsr = new XmlSerializer(typeof(Base));

        var b = new Base
        {
            children = new List<Child>
                {
                    new Child { Name= "Joe"},
                    new Child { Name ="Jack"},
                }
        };
        using (var ms = new MemoryStream())
        {
            xsr.Serialize(ms, b);

            var str = Encoding.UTF8.GetString(ms.ToArray());
            /*
            <?xml version="1.0"?>
            <Base xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
              <Child>
                <Name>Joe</Name>
              </Child>
              <Child>
                <Name>Jack</Name>
              </Child>
            </Base>
             */
        }
    }
}

public class Base
{
    [XmlElement("Child")]
    public List<Child> children;
}

public class Child
{
    public string Name;
}
Matthew Whited
  • 22,160
  • 4
  • 52
  • 69
  • Just to add on: if there is a need to further promote content from within the list items, the `XmlTextAttribute` can be applied to properties in `Child`, to to serialize as: `JoeJack` – Austin Drenski May 03 '17 at 22:05
2

You can use the XmlElementAttribute as follows:

public class Base
{
    [XmlElement("Child")]
    public List<Child> children;
    ...elided...
}

public class Child
{
    public string Name;
    ...elided...
}
P. Kouvarakis
  • 1,893
  • 12
  • 21
0

Edit: The other solutions are better and more direct answers to your question. However, I'm going to leave this here, as extending List<> rather than including a public List member can be a good idea in some cases. And it is possible solution.

Well, you could implement IXmlSerializable, but that might be overkill for what you're looking to do. Alternately, you could make Base extend List<Child>.

public class Base : List<Child>
{
}

This will, of course, change how you reference the children in the rest of your code. If you had base.children[0], you would instead use base[0].

Chris Berger
  • 557
  • 4
  • 14