raw_input A = 10, if A == 10 giving false: Python

Question

A = raw_input("5 + 5 =")

if A == 10:
    print "$"
elif A <> 10:
    print "!"

when I input 10 I also get "!" why?

`<>` is deprecated, use `!=` instead. – Daniel Apr 26 '17 at 17:00 — Daniel, Apr 26 '17 at 17:00

score 3 · Answer 1 · answered Apr 26 '17 at 16:59

3

raw_input returns a string, so you're getting back "10" (according to my terminal).

10 == '10' yields false. You need to cast the input to a number.

A = int(raw_input("5 + 5 ="))

answered Apr 26 '17 at 16:59

Sterling Archer

score 1 · Answer 2 · answered Apr 26 '17 at 16:59

1

Because the result of your call to raw_input is a string, not an integer.

You are comparing 5+5 == "10", which is false.

Trying using the int("str") function to convert your input to a number.

answered Apr 26 '17 at 16:59

aghast

2 Answers2