Php variable random definite value

Question

I try to create a variable who send a random value !

 $random = mt_rand(5,10);

but i want the variable random with the number i choose like this:

$random = 5;10;15;20;25;30

The variable must send randomly 5 or 10 or 15 or 25 or 30 only

It has answers [here](http://stackoverflow.com/questions/1643431/how-to-get-random-value-out-of-an-array) and [here](http://stackoverflow.com/questions/4233407/get-random-item-from-array) — am.rez, Apr 24 '17 at 11:35

score 1 · Answer 1 · answered Apr 24 '17 at 11:30

1

Like that?

$random = mt_rand(1,6) * 5;

answered Apr 24 '17 at 11:30

Paladin

1,637
13
28

score 1 · Accepted Answer · answered Apr 24 '17 at 11:31

1

What you could do is using the mt_rand function with values from 1 to 6 then multiply them by 5.

Example:

$random = mt_rand(1, 6) * 5;

answered Apr 24 '17 at 11:31

Ad5001

748
5
19

score 1 · Answer 3 · answered Apr 24 '17 at 11:32

1

Use array_rand to pick random key from array then you can put it into an another.

http://php.net/manual/en/function.array-rand.php

$input = array(5,10,15,20,25);
$rand_key = array_rand($input);
$another_array[] = $input[$rand_key];

answered Apr 24 '17 at 11:32

Peter

748
6
20

This has the advantage that it allows you to update the numbers when needed, rather than needing to work out the calculation for it, such as if you needed 13 adding at some stage. – gabe3886 Apr 24 '17 at 11:33
Yes, this is only one approach there is a lot. I wanted to show something like alternative solution :) It depends on the real cause what uses needed that :) – Peter Apr 24 '17 at 11:37

score 0 · Answer 4 · answered Apr 24 '17 at 11:32

0

You could use and array of element and get a random item

   $items = Array(5,10,15,20,...50);

    $myvalue = array_rand($items);

answered Apr 24 '17 at 11:32

ScaisEdge

131,976
10
91
107

score 0 · Answer 5 · answered Apr 24 '17 at 11:33

Assuming that you already have the values you want inside an array you can simply get a random position of the array. A rand() limited by the first element to the size of the array can solve this

<?php

$valores = [1,5,12,17,22,30,90,2,4,6]; // choose de values here

for($i=0;$i<200;$i++){ // just to print more than 1 value 
    echo $valores[rand(1,sizeof($valores))-1]."<br>"; // really pick the values here. start in 1 because we'll remove 1 
}

score 0 · Answer 6 · answered Apr 24 '17 at 11:33

Will it always be steps of 5? Then you could do something like

$random = mt_rand(1,6) * 5;

Otherwise I'd put the numbers that you want to choose from in an array and select a random element using mt_rand():

$random_temp = array(3,6,8,13,16,19);
$random = $random_temp[mt_rand(0,6)];

score 0 · Answer 7 · answered Apr 24 '17 at 11:36

0

If the random numbers arrayed, then this may help:

$list=array(5,10,15,20,25,30);
$n=count($list)-1;
$random=$list(rand(0,$n));

answered Apr 24 '17 at 11:36

Amir Ghorbani

29
3

score 0 · Answer 8 · answered Apr 24 '17 at 11:37

0

$values = [5,10,15,20,25,30];
//shuffle the array
shuffle($values);
foreach($values as $v){
  print $v;
}

always in different order...

answered Apr 24 '17 at 11:37

JustOnUnderMillions

3,741
9
12

score 0 · Answer 9 · answered Apr 24 '17 at 11:41

0

You can use rand():

$random = rand(1, 6) * 5;

Will produce:

5, 10, 15, 25 or 30 randomly.

answered Apr 24 '17 at 11:41

Pedro Lobito

94,083
31
258
268

score 0 · Answer 10 · answered Apr 24 '17 at 11:46

0

Please try this code

$random = rand(0,30);

if(($random%5)==0)
{
    echo $random;
}
else
{
    echo roundUpToAny($random);
}
function roundUpToAny($n,$x=5) {
    return round(($n+$x/2)/$x)*$x;
}

answered Apr 24 '17 at 11:46

sreeja seguro

16
1

Php variable random definite value

10 Answers10