How can I randomly generate 2 colors?

Question

I am making a RISK game in unity. I have 42 sprites of countries, and I have to generate random colors for each one, for example for 2 players 21 green and 21 red.

How can I generate color randomly ?

{
    this.GetComponent<SpriteRenderer>().color = Color.green;
}
    else
{

    this.GetComponent<SpriteRenderer>().color = Color.red;
}

Answer 1

This can easily be done with Unity's UnityEngine.Random.Range function.. Generate Random number between 0 and 1. Make 0 to be red and 1 to be green.

Color getRandomColor()
{
    //0 = red
    //1 = green
    if (UnityEngine.Random.Range(0, 2) == 0)
        return Color.red;
    else
        return Color.green;
}

Usage:

this.GetComponent<SpriteRenderer>().color = getRandomColor();

EDIT:

I deploy them equally

I guess you mean generate the random number equally. 12 red and 12 green and the-same time randomly.

Use this class:

public class EquallyColorGen
{
    const int totalNumber = 24;

    static bool[] randomNumbers = new bool[totalNumber];
    static Color[] randomColor = new Color[totalNumber];

    public static Color[] generateRandomNumbers()
    {
        const int halfOfTotalNumber = totalNumber / 2;

        int firstRandom = UnityEngine.Random.Range(0, 2);

        bool first12;
        bool last12;

        if (firstRandom == 0)
        {
            first12 = true;
            last12 = false;
        }
        else
        {
            first12 = false;
            last12 = true;
        }

        //Generate Even Random number. The first 12 are the-same. The last 12 are different but the-same
        for (int i = 0; i < randomNumbers.Length; i++)
        {
            randomNumbers[i] = (i < halfOfTotalNumber) ? first12 : last12;
        }

        //Shuff Amount
        const int shuffleAmount = 1;

        for (int j = 0; j < shuffleAmount; j++)
        {
            for (int i = 0; i < halfOfTotalNumber; i++)
            {
                //0 = flip color
                int randColor = UnityEngine.Random.Range(0, 2);
                bool flip = false;

                flip = (randColor == 0) ? true : false;

                //Also flip the 1 to 12
                randomNumbers[i] = (flip == true) ? !randomNumbers[i] : randomNumbers[i];

                //Also flip the other side 12 t0 24
                int lIndex = i + halfOfTotalNumber;
                randomNumbers[lIndex] = (flip == true) ? !randomNumbers[lIndex] : randomNumbers[lIndex];
            }
        }

        //Finally Make color from the list
        for (int i = 0; i < randomNumbers.Length; i++)
        {
            //Red = false
            //Green = true
            randomColor[i] = (randomNumbers[i] == false) ? Color.red : Color.green;
        }

        return randomColor;
    }
}

Usage:

Color[] randomPlayerColors = EquallyColorGen.generateRandomNumbers();

There are 24 random colors in the randomPlayerColors variable and they are generated equally. If you want 42 random colors, simply change const int totalNumber = 24; to const int totalNumber = 42;

Answer 2

Well I would make a different approach.

A controller object (not a sprite, just an invisible object that will hold some necessary scripts as in editor game logic interfaces) should have a script that will get all country GameObjects and shuffle them randomly in a list and divide between colors of how many players there are (like first half to a player 1, second...)

To shuffle a list:

List<CountryScript> countryList = new  List<CountryScript>();
countryList.AddRange(GetComponents<CountryScript>());
List<CountryScript> shuffledCountryList = new  List<CountryScript>();
while(countryList.Count > 0) {
    CountryScript c = countryList[Random.Range(0, countryList.Count)];
    shuffledCountryList.Add(c);
    countryList.Remove(c);
}

At the end of this you have an empty countryList and full shuffledCountryList. Any devision you can do in foreach loop like:

int playerCount = 2;
int maxNum = shuffledCountryList.Count / playerCount;
//It can be 2 or whatever you'll have it later
for(int i = 0; i < shuffledCountryList.Count; i++) {
    shuffledCountryList[i].SetPlayer(i/maxNum);
}

The CountryScript should have a public void SetPlayer(int Num) {} method that will color to a player specific color by an int Num value. Will you store this list on that Controller script in a property to be able to tweak it in editor or have it hardcoded in CountryScript is your choice. I'd go first way, since this way you can easily add more players + edit without coding. Or like Programmer wrote:

(Num == 0) ? Color.red : (Num == 1) Color.green : Color.blue;

Hope this helped you.