Print getcwd path

Question

My instructions are pretty clear, but I'm doing it wrong, can you help correct my error?

Instructions: else if (“pwd”) declare a char variable array of size MAX_PATH_LENGTH to hold the path do a getcwd print the path

my code:

 }else if(strcmp(argv[0],"pwd")){
        char arr[MAX_PATH_LENGTH];
        char getcwd(arr,MAX_PATH_LENGTH);
        printf("cwd: %s",arr);

`char getcwd(arr,MAX_PATH_LENGTH);` => `getcwd(arr, MAX_PATH_LENGTH);`. Also you should check the return value before printing the value. — Sergej Christoforov, Apr 20 '17 at 08:51
`if(strcmp(argv[0],"pwd"))` means "if the strings are unequal". And I wonder where `argv[0]` comes from. If it is an argument of `main` then `argv[0]` is the executable's name. — Weather Vane, Apr 20 '17 at 08:51
What do you intend to do at this line char getcwd(arr,MAX_PATH_LENGTH); ?? — Mohammed Bakr Sikal, Apr 20 '17 at 08:56
Please post code that actually compiles. The line `char getcwd(arr,MAX_PATH_LENGTH);` is a function declaration, that is missing the parameter types, not a call to the function. — JeremyP, Apr 20 '17 at 08:56

score 3 · Accepted Answer · answered Apr 20 '17 at 08:51

3

strcmp returns an integer and not a boolean.

int strcmp (const char* str1, const char* str2);

It returns a 0 if the two strings are equal, so you should be checking the returned value in your if statement like this:

if(strcmp(argv[0],"pwd")==0)

answered Apr 20 '17 at 08:51

1 Answers1