Currently i have byte array. Which contains a .jpg file also some other unwanted data.
What I wanted to do is to find out the position of data "FF D8" (start of JPEG data).
Same Code in iOS is : https://stackoverflow.com/a/18477915/5215474
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1downvoter? plz explain – Saranjith Apr 18 '17 at 11:41
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2Why do you think? Implementing this is *trivial*. So trivial that a Java programmer should not need to ask. Also ... asking someone to translate some code for you is NOT how StackOverflow is intended to be used. – Stephen C Apr 18 '17 at 11:46
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In objective C, I mean iOS it was not trivial right – Saranjith Apr 18 '17 at 11:47
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1Nope. But in Java it is. – Stephen C Apr 18 '17 at 11:48
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But need to know how we can check this substring – Saranjith Apr 18 '17 at 11:52
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1But nothing. It is simple Java 101 stuff. Anyone who calls themselves a Java programmer should be able to implement it in 2 minutes. Anyhow, you asked why the downvotes ... and I expect that is why. – Stephen C Apr 18 '17 at 11:54
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im iOS programmer.. just helping hands to juniors – Saranjith Apr 18 '17 at 11:57
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1Fine. So don't use StackOverflow as a free programming resource. If you are an iOS programmer and you need some Java programming done, either learn Java yourself, or employ a Java programmer. And if you are learning ... the way to learn is to do it yourself, not ask someone to do it for you. – Stephen C Apr 18 '17 at 11:59
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thanks for your time/.. maan.. actually i want get the image thats ol... fed up with wifi connection and getting from device and all... – Saranjith Apr 18 '17 at 12:00
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1Sorry. Bored now. Off to help someone else. You've had your 15 minutes of my time. – Stephen C Apr 18 '17 at 12:05
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hahah tahts good – Saranjith Apr 18 '17 at 12:26
1 Answers
3
This is trivial to implement in Java.
int position = -1;
for (int i = 0; i < bytes.length - 2; i++) {
if (bytes[i] == (byte) 0xff && bytes[i + 1] == (byte) 0xdf) {
position = i;
break;
}
}
Stephen C
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