When will encoders for map type be available?

Question

I'm trying to explore lot in Spark 2.0, so i'm curious to know "When will encoders for map type be available ?"

Thanks for your suggestion in advance. Vinoth.

This doesn't pertain to a programming problem. You probably won't get any better answer here than you would on Google. — Dylan Vander Berg, Apr 14 '17 at 04:36

score -1 · Answer 1 · answered Apr 13 '17 at 21:27

-1

For primitive types and case classes there are available since 1.6 like:

implicit val enc: Encoder[Map[String, Int]] = ExpressionEncoder()

For any other objects just use Kryo:

implicit val enc = org.apache.spark.sql.Encoders.kryo[Map[Any, Any]]

answered Apr 13 '17 at 21:27

user7864450

1 Answers1