Finding largest number in list using while loop (python)

Question

I have tried this code:

numbers = [1,2,5,8,4,99,3]

x = 0

while numbers[x+1] > numbers[x]: 
    x = x+1

print numbers[x]

The output is 8

Howcan I fix that?

do you need to use a while loop? max(numbers) will give you what you need if not. — chatton, Apr 13 '17 at 11:57
Your question already has an answer in the question here: http://stackoverflow.com/questions/12766077/python-finding-the-largest-number-in-a-list-using-forloop-or-while-loop — Thierry Lathuille, Apr 13 '17 at 12:03

score 1 · Answer 1 · answered Apr 13 '17 at 11:59

1

Try this:

numbers = [1,2,5,8,4,99,3]

x = 0
lar = numbers[x]
while x < len(numbers):
  if numbers[x] > lar:
    lar = numbers[x]
  x = x+1
print lar

answered Apr 13 '17 at 11:59

Ajay Gupta

score 0 · Answer 2 · edited Apr 13 '17 at 12:36

0

a = [1,2,5,8,4,99,3]
x = 0 
y = 0

while y != len(a):
    if x < a[y]:
        x = a[y]
    y += 1

print x

edited Apr 13 '17 at 12:36

Martin Evans

answered Apr 13 '17 at 12:32

Kallz

2 Answers2