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I am having trouble finding out what it means when you overload a type name. This is what I am talking about. 

using type_x = uint32_t;

//class instance variable initialized in constructor
type_x variable;

//later on in cpp file (this is my question)
inline ClassX::operator type_x () const { return variable; }
Bob Bobby
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1 Answers1

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The code in question is overloading a cast operator. It allows you to cast your class as the given type, in this case type_x, and receive a meaningful result.

You can find information here: http://en.cppreference.com/w/cpp/language/cast_operator

Mikel F
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