clone doctrine ArrayCollection without reference

Question

When I do

$originalTags = $task->getTags();
$task->removeTag($tag1);

then $tag1 is also removed in $originalTags. So the assignment of ArrayCollections is made by reference, how can I clone it to a new ArrayCollection?

http://php.net/manual/en/language.oop5.cloning.php – DrKey Apr 07 '17 at 15:44 — DrKey, Apr 07 '17 at 15:44
Is $task a doctrine entity? – RonnyKnoxville Apr 07 '17 at 15:58 — RonnyKnoxville, Apr 07 '17 at 15:58
@drkey cool, very easy, you can post this as answer – Asara Apr 07 '17 at 16:27 — Asara, Apr 07 '17 at 16:27

score 3 · Accepted Answer · answered Apr 07 '17 at 16:30

3

You can simply use native PHP clone for object cloning.

$originalTags = $task->getTags();
$task2 = clone $task;
$task2->removeTag($tag1);

answered Apr 07 '17 at 16:30

DrKey

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score 0 · Answer 2 · answered Apr 07 '17 at 15:25

0

I might have found the solution myself, but I don't know if this may result in any problems because I could lose data:

$originalTags = new ArrayCollection( $task->getTags()->toArray() );

answered Apr 07 '17 at 15:25

Asara

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score 0 · Answer 3 · answered Apr 07 '17 at 15:57

Rather than handling this problem individually every time you need getTags(), return a clone from getTags rather than the reference.

public function getTags(){
     return new ArrayCollection($this->tags->toArray());
}

or if you need to preserve the functionality of getTags passing by reference, create a new function getClonedTags or pass a variable to the get function which will optionally return cloned tags.

public function getTags($cloned = false){
    if($cloned){
        return new ArrayCollection($this->tags->toArray());
    }

    return clone $this->tags;
}

clone doctrine ArrayCollection without reference

3 Answers3