Catch SocketTimeOutException In cxf Jaxrsclient

Question

I am making a rest call using apache cxf . I am able to set timeout during invoking a service and corresponding socketConnection timeout exception gets thrown but i am not able to catch the exception and set it as user definied exception. Please find the below code for time out exception

try{
    HTTPClientPolicy clientConfig = WebClient.getConfig(service).getHttpConduit().getClient(); clientConfig.setReceiveTimeout(10000);} 
catch(SocketTimeOutException e) {
          logger.error("");
         CustomException....
    }

Exception gets thrown without going inside catch block. Could someone tell me how can i catch this exception?

Add another catch statement `catch(Exception ex) { ex.printStackTrace(); }` and you will know what exception is being thrown. — Winter, Apr 06 '17 at 17:01

score 0 · Answer 1 · edited Apr 06 '17 at 18:59

0

try to write

catch(Exception e) {
      logger.error("");
     CustomException....
}

instead of your code. Then you can catch the exception and handle it.

edited Apr 06 '17 at 18:59

Kenster

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answered Apr 06 '17 at 17:13

eng.MahmoudAlali

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I tried catching it as you mentioned but not working. – user6543599 Apr 06 '17 at 17:15
the problem could be in the http connection not in your code – eng.MahmoudAlali Apr 06 '17 at 17:19
I am making a mock service n hitting it by myself and i am able to receive response . Timeout is even working. Only issue is how can i catch the timeout – user6543599 Apr 06 '17 at 17:22

Catch SocketTimeOutException In cxf Jaxrsclient

1 Answers1