XMLParser enclosure attributes for AEXML library

Question

I am using a XMLParser Library. I have a xmlDoc and I don't know how can handle some tag values. For example:

<item>
<title>.....</title>
<description>....</description>
</item>

If I have like above xml works fine. But when I want to parse like below xml I cant do it.

<item>
 <enclosure type="image/jpeg" url="https://www....."/>
 <link rel="alternate" type="text/html" href="https://www"/>
</item>

Library url: AEXML

I can retrieve like this:

if let items = xmlDoc.root["item"].all{
for item in items{
print(item["title"].string)
}
}

But I dont know how can get enclosure. Anyone can help me?

Actually I dont know how can retrieve enclosure url. @dprogramz — Mayday, Apr 05 '17 at 18:17
The main page of the library you linked to shows an example of getting the attributes of an element. — rmaddy, Apr 05 '17 at 18:32
@rmaddy I updated my question, I cant get as attribute. Do you show me an example? — Mayday, Apr 05 '17 at 18:54
As I said, there is an example at https://github.com/tadija/AEXML — rmaddy, Apr 05 '17 at 18:56
@rmaddy print(xmlDoc.root["cats"]["cat"].attributes["breed"]!) I cant apply this for me. Thus, I said can you give me example. — Mayday, Apr 05 '17 at 19:05

score 1 · Accepted Answer · answered Apr 05 '17 at 19:52

1

Simply apply the example to your XML:

for item in items{
    if let enclosure = item["enclosure"] {
        if let url = enclosure.attributes["url"] {
        }
    }
}

answered Apr 05 '17 at 19:52

rmaddy

1 Answers1