getting part of current page url in php

Question

I have a url something like this:

http://example.com/a/b/c.php

If I do a $_SERVER['HTTP_HOST'], I get example.com

If I do a $_SERVER['REQUEST_URI'], I get a/b/c.php

But I want output as example.com/a/ I am assuming I will have to use some regex, not exactly sure how.

Any suggestions are welcome. Thank you :)

Just combine `$_SERVER['HTTP_HOST']` and `$_SERVER['REQUEST_URI']` you will get url — Saty, Apr 05 '17 at 05:33
Possible duplicate of [Get part of the current url PHP](http://stackoverflow.com/questions/19259219/get-part-of-the-current-url-php) — mayersdesign, Apr 05 '17 at 05:37
@mayersdesign yea you are possibly right, wonder how come I didn't get to that first before posting here — Anusha, Apr 05 '17 at 05:38
@Anusha if any of the below answer helped you with this, consider marking it as answer — Sagar V, Apr 05 '17 at 05:41

score 2 · Accepted Answer · answered Apr 05 '17 at 05:33

2

I would use explode:

<?php
$url = $_SERVER['HTTP_HOST'] . '/' . explode('/',$_SERVER['REQUEST_URI'])[1];
echo $url;
?>

answered Apr 05 '17 at 05:33

Neil

@SagarV Do you see what the OP just posted? "this seems to work :) thanks! " – Neil Apr 05 '17 at 05:42

score 2 · Answer 2 · answered Apr 05 '17 at 05:36

Or In regex way, you may do it like this:

^http(?:s)?:\/\/\K([^\/]+\/[^\/]+\/).*$

Demo

Sample Source (Run Here)

$re = '/^http(?:s)?:\/\/\K([^\/]+\/[^\/]+\/).*$/m';
$str = 'http://example.com/a/b/c.php';
preg_match($re, $str, $matches);
echo $matches[1];

2 Answers2