Java convert a HEX String to a BigInt

Question

Hi am trying to convert a hex string such as String hexStr = "1b0ee1e3"; to a bigInt, ideally i'd like to convert hexStr to a bigint in its decimal form,

I can convert a string to a bigInt w/o issues but when the string contains hex values i run into problems

Some of that doesn't make sense. There is no such thing as a 'BigInt in its decimal form'. The form of a BigInt is binary. — user207421, Nov 30 '10 at 22:13
when i pass in a string to a bigint in hex form its converted to its decimal form! try it — user524156, Dec 02 '10 at 14:00

Jon Skeet · Accepted Answer · 2010-11-30T17:42:17.237

75

Have you tried:

BigInteger bigInt = new BigInteger(hexString, 16);

For example:

import java.math.*;

public class Test {
    public static void main(String[] args) {
        String hexStr = "1b0ee1e3";
        BigInteger bigInt = new BigInteger(hexStr, 16);
        System.out.println(bigInt); // Prints 453960163
    }
}

edited Nov 30 '10 at 17:42

answered Nov 30 '10 at 17:36

Jon Skeet

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Excellent, all i was missing was the 16 to declare the input as hex!!,Thanks Jon – user524156 Nov 30 '10 at 18:31

Java convert a HEX String to a BigInt

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