I'm new to PIC programming and I'm using MPLAb. I have a question regarding interrupt.. so What I want to do, when I push a button then I want to turn on LED 0, and if I release the button then turn on LED 1. I thought the code I wrote making sense but it didn't work.
Here is what happens. Let say the initial state of interrupt pin is low (0), when a button is pushed. Then the LED 0 is on, and when I release the button then LED 1 is on. When I push the button again, I expect LED 0 is on, but LED 1 stays on, and never change the state.
I added last line to see the state of interrupt pin, and once the interrupt is high, it never change it to low.. Can you please advise me what is my misunderstanding?
Thanks in advance!
Here is my code:
void interrupt ISR(void)
{
if(INTCONbits.INTF)
{
nextLED = 1;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
else
{
nextLED = 0;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
nextLED = INTCONbits.INTF + 2;
LATC = Output_Code_Buffer[nextLED];
__delay_ms(250);
}
// Interrupt Enable settings
INTCONbits.INTE = 1;
INTCONbits.TMR0IE = 1; // Enable TMR0 interrupts
INTCONbits.TMR0IF = 0; // Clear TMR0 interrupt flag
INTCONbits.GIE = 1; // Enable global interrupts