In jupyter,I have the following code to create a slider control for my variable r using ipywidgets.
from ipywidgets import interact, interactive, fixed, interact_manual
import ipywidgets as widgets
r = 0.9992
def sl(r=0.9992):
global ar
ar = r
interact(sl, r=(0.999, 1, 0.0001))
It works but the problem is that the display of slider value is rounded to 2 decimal. As a result, the display always show 1.00.
Is there any way to display its actual value?
Since the version 6.x of ipywidgets, FloatSlider contains readout_format attribute. Just set it to your desired precision, e.g. like this:
widgets.FloatSlider(value=7.5, min=0, max=10.0,
step=0.001, readout_format='.3f')
Found solution here
Values are somehow computed on the way and maybe it's not possible to do it with FloatSlider. You can use SelectionSlider instead of Float.
my_values = [i / 1000 for i in range(10)] # [0.001, 0.002, ...] Or use numpy to list
SelectionSlider(options=[("%g"%i,i) for i in my_values])
Your code works if your function has a return value and it displays the precision you want to see in a label below (as in image)
mostly from info @ http://test-widgets.readthedocs.io/en/latest/examples/Using%20Interact.html
from ipywidgets import *
from IPython.display import display
def SL(r):
return r
interact(SL,r=widgets.FloatSlider(value=0.9992,min=0.9990,max=1.0000,step=0.0001,description='Precision:',))
