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I have a class that consists of a parameterized constructor which I need to call while creating an object. The class also contains a private copy constructor restricting to create an object to it. Now how to call the paramter constructor of this class. I think we can create a pointer reference to the class. But how to call the parameter constructor using the reference?

My Program:

#include<iostream>
#include<string>
using namespace std;

class ABase
{
protected:
    ABase(string str) {
        cout<<str<<endl;
        cout<<"ABase Constructor"<<endl;
    }
    ~ABase() {
    cout<<"ABASE Destructor"<<endl;
    }
private:
    ABase( const ABase& );
    const ABase& operator=( const ABase& );
};


int main( void )
{
    ABase *ab;//---------How to call the parameter constructor using this??

    return 0;
}
Hema Chandra
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2 Answers2

1

The syntax you need is ABase *ab = new ABase(foo); where foo is either a std::string instance or something that std::string can take on construction, such as a const char[] literal, e.g. "Hello".

Don't forget to call delete to release the memory.

(Alternatively you could write ABase ab(foo) if you don't need a pointer type.)

Bathsheba
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1

You can't do this. Because your ctor is protected. Please see (not related with your state, but only to learn more): Why is protected constructor raising an error this this code?

Community
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Yusuf R. Karagöz
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