Literal for ranges in C++11

Question

If I have this:

for (auto iSong = 1; iSong <= iMaxSongNumber; iSong++)

Can I use the new for range approach?

I understand that for containers they need a begin and end method for them to work. But if we have literal max values?

Ranges are not native to C++11, but there are libraries that can create them (and which can be used for e.g. ranged `for` loops). — Some programmer dude, Mar 20 '17 at 09:46
Sorry for that, it was not so clever joke about expecting "rangers" in c++. — Kuba Wyrostek, Mar 20 '17 at 09:58
You need something like [`counting_range`](http://stackoverflow.com/a/28099607/752976), but that's not in the standard. Use Boost or write your own. — Bartek Banachewicz, Mar 20 '17 at 10:31

score 1 · Accepted Answer · answered Mar 20 '17 at 11:16

1

There isn't a built-in mechanism to do this: range-based for works on something for which begin and end can be called.

Basically, you need to create a "virtual container" with iterators that update the count.

answered Mar 20 '17 at 11:16

Anthony Williams

Thanks for the information you have provided. I don't think it is worth the effort for my needs. If there was something out of the box ... Also, in my instances I also need 1 stated indexing as opposed to 0 based. But thank you anyway. I will accept this answer. – Andrew Truckle Mar 20 '17 at 11:29
The final code linked to from the blog post allows 1-based indexing. https://www.justsoftwaresolutions.co.uk/files/numeric_range.cpp – Anthony Williams Mar 20 '17 at 11:56

1 Answers1