Receving a value from AXI connected to UART

Question

On ISE 14.7, what do I need to do in order to have the AXI stream (which has an ipcore that loops a value) to give me output via the UART?

I had set up the project properly, added a UART and set the mhs, ucf files and the rest of the bonanza, however I do not have any idea what do I need to do to have output from the AXI via the UART.

Any ideas?

Just a coursework assignment, no guide for, not even a clue on how to start it. It is a bit of a try and guess situation... — Joe Carr, Mar 14 '17 at 06:18

score 1 · Accepted Answer · answered Mar 14 '17 at 04:24

1

You will need to write an UART module in RTL or use an existing Ip-core which accepts AXI-stream transaction and converts it to UART messages.

However due to performance differences it is more common to find IP-cores with AXI4-Lite interface to UART. For example AXI UART 16550 (https://www.xilinx.com/support/documentation/ip_documentation/axi_uart16550/v2_0/pg143-axi-uart16550.pdf)

answered Mar 14 '17 at 04:24

Robbie Vincke

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I will try it out now! – Joe Carr Mar 14 '17 at 06:20
Can you elaborate on what is wrong ? which IP are you using ? what is the error message ? – Robbie Vincke Mar 15 '17 at 04:42
The IP I am to use a is custom made one and by the looks of it, it has been produced in Matlab. – Joe Carr Mar 15 '17 at 06:34
In the *.h file it just has some address values in hex (e.g #define IPCore_Enable_const_axi_ip 0x4). Perhaps I would need to use them in some way? – Joe Carr Mar 15 '17 at 06:36

Receving a value from AXI connected to UART

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