Print negated words that follows "no,not,never" in a sentence in Python

Question

How do I print all negated word that follows "no","not", "never" so on. The sentence is

SENTENCE="It was never going to work.I'm not happy"

Desired output

going,happy (Which follows never and not)

Any help !

Welcome to StackOverflow! Please keep in mind that this is not a "code this for me" website. Please show us what you already did and tell us where your problems lie. — Alfe, Mar 09 '17 at 12:56

score 2 · Accepted Answer · answered Mar 09 '17 at 13:00

You may not need ntlk for that. I'd split the string (using regex to split according to non-alphanums (or you have an issue with work.I'm part), and build a list comprehension which looks for the previous word belonging to the "negative" words.

import re

SENTENCE="It was never going to work.I'm not happy"

all_words = re.split("\W+",SENTENCE)

words = [w for i,w in enumerate(all_words) if i and (all_words[i-1] in ["not","never","no"])]

print(words)

result:

['going', 'happy']

Thank you. Its a great Solution – Chathuri Fernando Mar 09 '17 at 13:04 — Chathuri Fernando, Mar 09 '17 at 13:04

Print negated words that follows "no,not,never" in a sentence in Python

1 Answers1