I'd like to count the number of non integers in double array. For example
Input: mylist=[['a',-2,'b',-3,1],['c','a',-1,1,3],['d','f'],['e',3],[-11]]
Output: num_value(mylist)=7
Show me how to make it.
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Micheal C
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Could you please show us your own attempt to get Python code to reach to a solution – Elmex80s Mar 08 '17 at 15:53
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1I really don't see why this is downvoted so much. I've seen "wall of code" questions with 1 upvote... – Jean-François Fabre Mar 08 '17 at 15:55
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I believe most voters like to see some effort on the questioners part. – Eric S Mar 08 '17 at 15:57
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the fact that the question is clear is more important than the effort. – Jean-François Fabre Mar 08 '17 at 15:59
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check that one, makes me arrrrghhh (warning wall of code ahead): http://stackoverflow.com/questions/42676242/python-functions-and-variables-trouble – Jean-François Fabre Mar 08 '17 at 16:08
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another bad one: http://stackoverflow.com/questions/42676367/how-to-make-this-code-menu-operated-python – Jean-François Fabre Mar 08 '17 at 16:13
1 Answers
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Count instances of non-integers in the lists of lists (using double for in generator comprehension fed to sum)
mylist=[['a',-2,'b',-3,1],['c','a',-1,1,3],['d','f'],['e',3],[-11]]
print(sum(1 for sl in mylist for x in sl if not isinstance(x,int)))
yields: 7
Jean-François Fabre
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@Ev.Kounis so your code is correct :) and thx for the upvote (I would have done the same, since the question is really not that bad!) – Jean-François Fabre Mar 08 '17 at 15:56
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I though of making a function out of it as in the OPs example and that cost me. never again – Ma0 Mar 08 '17 at 15:59
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