how to get file name from URI

Question

Hello I am develop video player with android gallery. I receive URI from gallry. and I need to display video title, when play video. so if content has not title meta data. I need to disaplay video file name. How to get video content file name?

thank you

So you want to display the URI? Or split it by / and display the last part? — Mikhail, Nov 24 '10 at 02:42
I want to display last part. if I display URI vALUE is /external/video/media/3. but 3 is id. not file name. — byungkyu, Nov 24 '10 at 05:08
Look at this other post: [http://stackoverflow.com/questions/1105593/get-file-name-from-uri-string-in-c-sharp][1] [1]: http://stackoverflow.com/questions/1105593/get-file-name-from-uri-string-in-c-sharp — Jaime Botero, Dec 13 '11 at 14:21
Google's answer: https://developer.android.com/training/secure-file-sharing/retrieve-info.html — MechEthan, Apr 24 '15 at 23:32

score 28 · Answer 1 · edited Apr 09 '13 at 07:31

28

Here is the code for getting name of file from url

Uri u = Uri.parse("www.google.com/images/image.jpg");

File f = new File("" + u);

f.getName();

edited Apr 09 '13 at 07:31

Pratik

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answered Nov 24 '10 at 04:48

fargath

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Not working in my case it only gives the name at the end of the url but while fetching the documents from the files inside of the Google drive or somewhere else it returns the string after the last forward slash. – cammando Mar 09 '17 at 11:39

score 10 · Answer 2 · answered Apr 14 '15 at 01:07

Since none of the answers really solve the questions, i put my solution here, hope it will be helpful.

     String fileName;
     if (uri.getScheme().equals("file")) {
            fileName = uri.getLastPathSegment();
        } else {
            Cursor cursor = null;
            try {
                cursor = getContentResolver().query(uri, new String[]{
                        MediaStore.Images.ImageColumns.DISPLAY_NAME
                }, null, null, null);

                if (cursor != null && cursor.moveToFirst()) {
                    fileName = cursor.getString(cursor.getColumnIndex(MediaStore.Images.ImageColumns.DISPLAY_NAME));
                    Log.d(TAG, "name is " + fileName);
                }
            } finally {

                if (cursor != null) {
                    cursor.close();
                }
            }
        }

score 5 · Answer 3 · answered Apr 04 '18 at 14:24

If the uri is a content provider uri, this is how you should retrieve file info.

        Cursor cursor = getContentResolver().query(uri, null, null, null, null);
        /*
         * Get the column indexes of the data in the Cursor,
         * move to the first row in the Cursor, get the data,
         * and display it.
         */
        int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
        cursor.moveToFirst();
        nameView.setText(cursor.getString(nameIndex));

https://developer.android.com/training/secure-file-sharing/retrieve-info.html

How in the world is this the API? It looks like we're trying to reverse engineer some object. — topher217, Dec 10 '21 at 13:44

score 3 · Answer 4 · answered Sep 03 '20 at 22:15

3

For kotlin just simply:

val fileName = File(uri.path).name

answered Sep 03 '20 at 22:15

Sam Chen

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score 2 · Answer 5 · answered Jul 30 '17 at 19:39

Below code works for me in case of image from gallery, It should work for any file type.

    String fileName = "default_file_name";
    Cursor returnCursor =
            getContentResolver().query(YourFileUri, null, null, null, null);
    try {
        int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
        returnCursor.moveToFirst(); 
        fileName = returnCursor.getString(nameIndex);
        LOG.debug(TAG, "file name : " + fileName);
    }catch (Exception e){
        LOG.error(TAG, "error: ", e);
        //handle the failure cases here
    } finally {
        returnCursor.close();
    }

Here you can find detailed explanation and much more.

score 1 · Answer 6 · answered Jan 10 '16 at 13:14

1

try
        {
            String uriString = "http://somesite.com/video.mp4";
            URI uri = new URI(uriString);

            URL videoUrl = uri.toURL();
            File tempFile = new File(videoUrl.getFile());
            String fileName = tempFile.getName();
        }
        catch (Exception e)
        {

        }

answered Jan 10 '16 at 13:14

Ayaz Alifov

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Someone downvoted the answer. Could you, please, explain why? – Ayaz Alifov Apr 19 '17 at 11:44
@Grsmto, sorry, but did you even try to run the code before writing your comment? I think no, because I just checked your example url and it returned proper result - file.mp3 – Ayaz Alifov May 13 '17 at 02:58
I may be wrong, realised my Android Studio debugger is acting really weirdly...got some old cache of previous builds and all...I'll delete my answer. – adriendenat May 13 '17 at 20:06

score 1 · Answer 7 · answered Nov 24 '10 at 10:59

int actual_image_column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA); 
String filename = cursor.getString(actual_image_column_index);

This is example for Image . you can try same thing for your needs ( video).

Thanks & Best Luck :)

score 0 · Answer 8 · answered Feb 08 '21 at 06:53

Google reference:

https://developer.android.com/training/secure-file-sharing/retrieve-info#RetrieveFileInfo

        /*
         * Get the file's content URI from the incoming Intent,
         * then query the server app to get the file's display name
         * and size.
         */
        Uri returnUri = returnIntent.getData();
        Cursor returnCursor =
                getContentResolver().query(returnUri, null, null, null, null);
        /*
         * Get the column indexes of the data in the Cursor,
         * move to the first row in the Cursor, get the data,
         * and display it.
         */
        int nameIndex = returnCursor.getColumnIndex(OpenableColumns.DISPLAY_NAME);
        int sizeIndex = returnCursor.getColumnIndex(OpenableColumns.SIZE);
        returnCursor.moveToFirst();
        TextView nameView = (TextView) findViewById(R.id.filename_text);
        TextView sizeView = (TextView) findViewById(R.id.filesize_text);
        nameView.setText(returnCursor.getString(nameIndex));
        sizeView.setText(Long.toString(returnCursor.getLong(sizeIndex)));

score 0 · Answer 9 · answered Nov 03 '21 at 17:30

Try the following code,

    public String getFileName(Uri uri) {
        String result = null;
        if (uri.getScheme().equals("content")) {
            Cursor cursor = getContentResolver().query(uri, null, null, null, null);
            try {
                if (cursor != null && cursor.moveToFirst()) {
                    result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
                }
            } finally {
                cursor.close();
            }
        }
        if (result == null) {
            result = uri.getPath();
            int cut = result.lastIndexOf('/');
            if (cut != -1) {
                result = result.substring(cut + 1);
            }
        }
        return result;
    }

score -2 · Answer 10 · edited Mar 17 '15 at 08:17

Here i am giving you a sample code which will upload image from gallery

To extract filename/Imagename,Do the following

File f = new File(selectedPath);
System.out.println("Image name is   ::" + f.getName());//get name of file

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
switch (requestCode) {
case 1:
if (resultCode == YourActivity.RESULT_OK) {
Uri selectedImageUri = data.getData();
String selectedPath = getPath(selectedImageUri);
File f = new File(selectedPath);
System.out.println("Image name is   ::" + f.getName());//get name of file
}
}

Hope this will help

`getPath()` is a custom function, that is not listed in your code snippet — sweisgerber.dev, Jan 13 '17 at 10:35

how to get file name from URI

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