Python can't parse my list of ints

Asked Mar 01 '17 at 13:35

Active Mar 01 '17 at 13:35

Viewed 59 times

Im having some problem with a list of ints, it looks like this:

Its part of a bigger list, but when I try to go thru it line by line and parse it I get the following error:

ValueError: invalid literal for int() with base 10: '\xef\xbb\xbf85\n'

My code looks like:

with open("data.csv", "r") as ins:

    array = []

    for line in ins:
        print 'String: ', line

        print 'Integer: ', int(line)

If I try to catch the error with this code:

with open("data.csv", "r") as ins:

    array = []

    for line in ins:
        print 'String: ', line

        try:
            print 'Integer: ', int(line)
        except:
            print 'Non-integer: ', line

I get this output:

Anyone have a clue?

asked Mar 01 '17 at 13:35

Jason94

13,320
37
106
184

2

Can you post text as text, not as screenshots please? – khelwood Mar 01 '17 at 13:35
Looks like some of your lines contain secret invisible unicode characters. You should remove those before trying to convert to integer. – Kevin Mar 01 '17 at 13:37
1

bingo BOM header! – Jean-François Fabre Mar 01 '17 at 13:37
2

use `strip(line)` – Ma0 Mar 01 '17 at 13:37
Your line variable has "\n" also.Strip it . – pseudo_teetotaler Mar 01 '17 at 13:37
1

@Ev.Kounis Actually try `int('2\n')`, it works, `int` ignores whitespace – Chris_Rands Mar 01 '17 at 13:44
@Ev.Kounis strip is a function in a library? line.strip() does not solve anything for me :( – Jason94 Mar 01 '17 at 13:52

Python can't parse my list of ints

0 Answers0