Skip to next loop if matches condition in groovy

Question

I'm very new to groovy so please excuse if its a silly question.

I'm parsing a XML file and fetching the fruit names to a list. My incomplete code snippet below.

....
....
def xmlOutput = proc.in.text
def lists = new XmlSlurper().parseText(xmlOutput)
def listOffruits = lists.fruits.entry.name

//Below is the fuit list for which I want to skip the loop
def myList = ["orange", "apple", "banana", "grapes"]

listOffruits.each(){
  def fruitName = it.text()
    //Not sure how on the logic
println "- found Fruit Name not on the list'${fruitName }'"
}

I want to check/compare if the fruit name is present in the list - "myList" , if present skip the loop or move on to next iterator ,if not continue with the loop.

I'm not sure how exactly to achieve it. Any suggestions pls. Thanks.

Possible duplicate of http://stackoverflow.com/questions/3049790/break-from-groovy-each-closure — Nitesh Goyal, Mar 01 '17 at 10:24
@Nitesh , Thanks, but i want to compare/check every value of list - listOffruits to the values in the another list - myList . — voltas, Mar 01 '17 at 10:36

score 2 · Accepted Answer · answered Mar 01 '17 at 11:44

2

You can use findAll to just keep the fruit not in the list...

def unfoundFruits = listOffruits.findAll { f -> !myList.contains(f) }
unfoundFruits.each { f ->
    println "- found Fruit Name not on the list '${f}'"
}

answered Mar 01 '17 at 11:44

tim_yates

167,322
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Worked like a charm, thanks for introducing me to the findAll method. Thanks!! – voltas Mar 01 '17 at 12:10

score 1 · Answer 2 · answered Mar 01 '17 at 12:22

1

You can use Collection#minus, for example:

def listOffruits = ["pineapple", "apple", "strawberry", "grapes"]
def myList = ["orange", "apple", "banana", "grapes"]
println "Fruits not on the list: ${listOffruits.minus myList}"

answered Mar 01 '17 at 12:22

m0skit0

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Skip to next loop if matches condition in groovy

2 Answers2