analyzing MSP430 code

Question

so if had the following statements in assembly for the msp430 with the rf2500 chip

0x0000c06a <+44>: 3f 40 22 00 mov  #34, r15; 0x0022

and

0x0000c07c <+62>: 3e 53      add #-1, r14; r3 As==11

how many bytes does each instruction occupy?

CL. · Answer 1 · 2017-03-01T18:50:51.930

2

The values of the six bytes are shown after the address:

                   ___________
0x0000c06a <+44>:  3f 40 22 00  mov  #34, r15; 0x0022
0x0000c07c <+62>:  3e 53        add  #-1, r14; r3 As==11
                   ^^^^^^^^^^^

edited Mar 01 '17 at 18:50

answered Mar 01 '17 at 05:27

CL.

173,858
17
217
259

so I would just add all those hex numbers together and divide by 8? – andrewF Mar 01 '17 at 17:52
or would it just be 4 for the first and 2 for the second? – andrewF Mar 01 '17 at 18:31

analyzing MSP430 code

1 Answers1