Is it a way to use constexpr with yaml-cpp ? I tried :
constexpr YAML::Node sample = YAML::LoadFile("sample.yaml");
but it seems that's not possible with the actual implementation of yaml ?
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2I doubt it's going to be possible with *any* implementation of YAML. `constexpr` is used to define compile-time constants, or expressions able to produce compile-time constants. There is no way how the result of `YAML::LoadFile(…)` might be known at compilation time. – ach Feb 27 '17 at 07:17
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If you do have a constexpr string, and if `YAML::Load` is a constexpr function, you could do `constexpr YAML::Node sample = YAML::Load("[1, 2, 3]");` – Caleth Feb 27 '17 at 11:25
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the idea was to use yaml data (from a file *.yml) in a template expression, in order to get some optimisations, but it's probably not possible. – Kafka Feb 27 '17 at 14:22