Clang tooling. Type name without keyword

Question

I'm working on some clang tool, and I need to generate source code with types, that aren't specified explicitly. The strings with types I get from clang::QualType is something like: class std::initializer_list<int>. The issue is to get type without keyword.

I've tried to dyn_cast<> types (clang::Type) to all heirs of TypeWithKeyword but the result is always null.

Of course I can delete all occurrence of "class", "struct", etc. from the string with type name, but I would like to solve this in "clang way".

score 3 · Accepted Answer · answered May 01 '17 at 20:54

The answer was simple. Instead of using QualType::getAsString(), just needed QualType::getAsString (const PrintingPolicy &Policy). So the code:

PrintingPolicy pp(f_context->getLangOpts());
string typeName = qualType.getAsString(pp);

Works well without changing fields of PrintingPolicy.

Clang tooling. Type name without keyword

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