A different flavor of Const Reference?

Question

what's the difference between std::vector<T> const & and const std::vector<T> & ?

I'm used to const T &, but this "T const &" is different to me.

and forgive me for my ignorance.

There is no difference, I like to use the 1st form, some people like the 2nd. This is also correct `const std::vector const &` and the same as above. — Richard Critten, Feb 25 '17 at 16:01
@RichardCritten: No, that's a syntax error: `duplicate 'const'` — Christian Hackl, Feb 25 '17 at 16:02
@Richard Critten: Applying the same qualifier twice directly (as in your example) is not allowed in C++. — AnT stands with Russia, Feb 25 '17 at 16:03

score 0 · Accepted Answer · answered Feb 25 '17 at 16:01

They are completely equal.

You can verify this by trying to compile the following code and see how the compiler complains about a redefinition:

#include <vector>

void f(std::vector<int> const &) {}
void f(const std::vector<int> &) {} // error: redefinition

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