Make CMTime with a very small value

Question

I have a small integer value and I want to convert it into CMTime.

The problem is that

CMTime(value: _ , timeScale: _)

or

CMTimeMakeWithSeconds(value: _ , timeScale: _)

will always return the floor so that time always equals 0.0 seconds

let smallValue = 0.0401588716
let frameTime = CMTime(Int64(smallValue) , timeScale: 1) 
//frameTime is 0.0 seconds because of Int64 conversion

let frameTimeInSeconds = CMTimeMakeWithSeconds(smallValue , timeScale: 1) 
// frameTimeInSeconds also returns 0.0 seconds.

what the output you expect – Anbu.Karthik Feb 23 '17 at 08:26 — Anbu.Karthik, Feb 23 '17 at 08:26
the same as the `smallValue` i.e `0.0401588716` – Feb 23 '17 at 08:33 — , Feb 23 '17 at 08:33

score 3 · Accepted Answer · answered Feb 23 '17 at 08:44

3

CMTime represents a time value as a rational number with integer numerator (the value) and denominator (the timescale) . In order to represent a small value like yours, you have to choose a larger timescale (depending on the desired accuracy). Example:

let smallValue = 0.0401588716
let frameTime = CMTime(seconds: smallValue, preferredTimescale: 1000000) 

print(frameTime.seconds) // 0.040158

answered Feb 23 '17 at 08:44

Martin R

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Thanks for the solution. I also found `CMTimeMultiplyWithFloat64(..)` works if a `CMTime(..) = 1 Sec` and `smallValue` is taken. – Feb 23 '17 at 09:03

score 1 · Answer 2 · edited Jan 12 '18 at 10:00

1

I should have put a little thought into it before posting the question.

 let smallValue =  0.0401588716
 let oneSec =      CMTimeMakeWithSeconds(1, timeScale: 1) 
 let frameTime =   CMTimeMultiplyByFloat64(oneSec , smallValue)
 print(CMTimeGetSeconds(frameTime))                              //  0.040158872

edited Jan 12 '18 at 10:00

mugx

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answered Feb 23 '17 at 08:51

Make CMTime with a very small value

2 Answers2

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