PHP Ternary operator with static call

Question

When I do:

$foo = (1 === 1) ? 'one' : 'not one';

Following expression gives me error though:

public static $relationsData = [
    'tasks' => (Module::isEnabled('Task')) ? [self::HAS_MANY, Task::class, 'foreignKey' => 'created_by'] : [],
];

What kind of error does it gives you ? because as long as the function returns a boolean, it si possible. — Nicolas, Feb 15 '17 at 18:36
The code that actually causes this error probably lies above this code and only manifests as an error on this line. We need to see the code above this. — John Conde, Feb 15 '17 at 18:41
i have updated the question with actual code that is giving error. — dev02, Feb 15 '17 at 18:42
You won't be able to set the static property that way. You can only use expressions that can be evaluated at compile time. It doesn't have anything to do with the ternary, though. — Don't Panic, Feb 15 '17 at 18:44
Also http://stackoverflow.com/questions/693691/how-to-initialize-static-variables?rq=1 — AbraCadaver, Feb 15 '17 at 18:47

Pejman · Answer 1 · 2017-02-15T18:52:11.937

The error you encounter is probably related to Module::isEnabled('Bar') and not to ternary operator. Whatever is condition of the ternary operator is evaluated first and ternary operator simply uses the result of that evaluation. Simply having Foo::bar() as condition should not cause any problem.

Edit after OP's update: As others have said, the problem here is you are assigning a non-trivial expression to a static class variable. The ternary operator is merely doing its job.

PHP Ternary operator with static call

1 Answers1