Not able to generate a chart-php

Question

I am creating bar chart , i am unable to get output and generate chart.

here is my code

if ($sql) {
    $arrData = array(
        "chart" => array(
            "caption" => "Status stastics",
            "showValues" => "0",
            "theme" => "zune"
        )
   );
   $arrData["data"] = array();

   foreach($sql as $row)  {
       array_push($arrData["data"], array(
           "label" => $row["name"],
           "value" => $row["value"]
       )
       var_dump($row["value"]);
       );
    }
}

I am not getting any output for ( var_dump($row["value"]);) am i going in a right way? Can any one help me in this.

yes, you put the var_dump in the `array_push` function. But there is no comma after the array with label and value to start with. I think this is a syntax error. Do you have error reporting on ? — Vasil Rashkov, Feb 14 '17 at 09:06
@VasilShaddix yes error reporting is on but i don't find any errors. — R9102, Feb 14 '17 at 09:14
but it shows fatal error--> Cannot use object of type stdClass — R9102, Feb 14 '17 at 09:16

score 1 · Accepted Answer · answered Feb 14 '17 at 11:41

Got my answer

if ($sql) {
$arrData = array(
"chart" => array(
"caption" => "Status stastics",
"showValues" => "0",
"theme" => "zune"
  )
  );
$arrData["data"] = array();

foreach($sql as $row)
{
$object_array =(array)$row;
array_push($arrData["data"], array(
"label" => $object_array["name"],
"value" => $object_array["value"]
 )
 );
}

}
?>

Not able to generate a chart-php

1 Answers1