Check if list with given items is present in dict

Question

I have a dict and a list like this:

hey = {'2': ['Drink', 'c', 'd'], '1': ['Cook', 'a']}
temp = ['Cook', 'a']

I want to check if temp is present in hey. My code:

def checkArrayItem(source,target):
    global flag
    flag = True

    for item in source:
        if (item in target):
            continue
        else:
            flag = False
            break
for i,arr in enumerate(hey) :
    if (len(temp) == len(hey[arr])):
        checkArrayItem(temp,hey[arr])
        if (flag):
            print('I got it')
            break

What is a more elegant way to do this check?

You mean you have a `dict` and a `list`. – khelwood Feb 08 '17 at 10:56 — khelwood, Feb 08 '17 at 10:56
thanks , I had see the link . – Relax ZeroC Feb 08 '17 at 12:10 — Relax ZeroC, Feb 08 '17 at 12:10

score 2 · Accepted Answer · answered Feb 08 '17 at 10:56

2

How about temp in hey.values()?

answered Feb 08 '17 at 10:56

barak manos

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thanks, excellete ans – Relax ZeroC Feb 08 '17 at 12:11
@RelaxZeroC: You're welcome. – barak manos Feb 08 '17 at 12:17

score 0 · Answer 2 · answered Feb 08 '17 at 10:57

0

Just use sets to compare to container entirely:

In [40]: hey = {'2': ['Drink', 'c', 'd'], '1': ['Cook', 'a']}

In [41]: temp = {'Cook', 'a'}
# This will give you the keys within your dictionary that their values are equal to tamp
In [42]: [k for k, v in hey.items() if set(v) == temp]
Out[42]: ['1']

answered Feb 08 '17 at 10:57

Mazdak

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thanks, it's good to use. – Relax ZeroC Feb 08 '17 at 12:11

Check if list with given items is present in dict

2 Answers2