POST Request Swift 3.0 Alamofire

Question

I am trying to do a .POST request with Alamofire in Swift 3. I´ve written the following function

func postToken(Token: String) {
    let parameters : [String:Any] = ["api_key":"ivaomobileapp", "function":"login", "IVAOTOKEN=":"\(Token)"]
    Alamofire.request("URL", method: .post, parameters: parameters, encoding: JSONEncoding.default, headers: nil).responseJSON { (response:DataResponse<Any>) in

        switch(response.result) {
        case .success(_):
            if let data = response.result.value{
                print(data)
            }
            break

        case .failure(_):
            print(response.result.error as Any)
            break

        }
    }
}

But the code doesn´t work, it gives the following error:

Alamofire.AFError.responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.jsonSerializationFailed(Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.}))

This is the same request in CURL(UNIX)

curl https://whatever -X POST -F 'api_key=ivaomobileapp' -F 'function=Login' -F 'IVAOTOKEN=whatever'

What am I doing wrong?

Thanks

@Anbu.Karthik This is what I am returning now: {"msg":"user login successfully entered."} — CTABUYO, Feb 04 '17 at 11:31
your `print(data)` is `"msg":"user login successfully entered."}` thsi — Anbu.Karthik, Feb 04 '17 at 11:33
@Anbu.Karthik But I still have the same issue, Alamofire.AFError.responseSerializationFailed(Alamofire.AFError.ResponseSerializationFailureReason.jsonSerializationFailed(Error Domain=NSCocoaErrorDomain Code=3840 "Invalid value around character 0." UserInfo={NSDebugDescription=Invalid value around character 0.})) — CTABUYO, Feb 04 '17 at 11:34
use ` .responseString instead of .responseJSON` and try once — Anbu.Karthik, Feb 04 '17 at 11:37
see this once also https://github.com/Alamofire/Alamofire/issues/1281 — Anbu.Karthik, Feb 04 '17 at 11:38
@Anbu.Karthik I fixed that problem. But now the parameters are not being correctly posted. — CTABUYO, Feb 04 '17 at 11:52

score 0 · Answer 1 · answered Feb 04 '17 at 11:02

0

Response from a server isn't valid json try using responseString, responseData or response to figure out what the issue is.

answered Feb 04 '17 at 11:02

Ram

961
6
14

I don't understand what you mean. I tried changing to responseData, same issue. – CTABUYO Feb 04 '17 at 11:07
my means the server side data is not valid JSON – Ram Feb 04 '17 at 11:08
What can I do to figure it out? – CTABUYO Feb 04 '17 at 11:10

Wolfgang Schreurs · Accepted Answer · 2017-02-04T15:55:31.403

0

I think you handle the addition of the IVAOTOKEN parameter in the wrong way, causing issues, perhaps creating a malformed dictionary. Perhaps your parameters should look like the following:

let parameters : [String:Any] = [
      "api_key": "ivaomobileapp", 
      "function": "login", 
      "IVAOTOKEN": Token
]

Alamofire will add the quotes around the Token variable, as it is a String. The result should be that the following is sent to the server:

{
    "api_key": "ivaomobileapp", 
    "function": "login", 
    "IVAOTOKEN": "TOKENVALUE"
}

edited Feb 04 '17 at 15:55

answered Feb 04 '17 at 15:49

Wolfgang Schreurs

11,779
7
51
92

I have a problem sending the api_key parameter, in the CURL request it is as follows 'api_key=ivaomobileapp'. Should I put somewhere the = in the Alamofire. Sorry, I´ve never done POST Requests with Alamofire :( – CTABUYO Feb 04 '17 at 16:11
Well, do you literally use the value `ivaomobileapp` for the `api_key` parameter? I would think a key would look actually look somewhat different. Maybe like some sort of random hash. Either way, the `=` sign should not be part of the parameter key. Alamofire will transform your parameters to valid JSON and as such will add the `=` sign between the key and the value. – Wolfgang Schreurs Feb 04 '17 at 16:13
I think you should make 100% sure you can use this value as API key, as it's highly unusual. Usually it's a random hash or some such. Especially if you compare it with API keys from Facebook, Twitter, Flickr, etc... – Wolfgang Schreurs Feb 04 '17 at 16:15
yeah completely sure, CURL works with that value. My Chinese partner made the API so maybe it´s a mistranslation between Mandarin and English. – CTABUYO Feb 04 '17 at 16:16
Well, another thing that's different with your curl request, is that in your curl request you actually don't send JSON, but you use a form request. So you might want to change a different kind of request. Or transform your curl request to a JSON request, if your server supports this. – Wolfgang Schreurs Feb 04 '17 at 16:20
Perhaps try a form request like here, that should be mostly similar with the curl request you are using: http://stackoverflow.com/a/37178808/250164 – Wolfgang Schreurs Feb 04 '17 at 16:25

POST Request Swift 3.0 Alamofire

2 Answers2