How do I generate a division operation where its result will have remainder 0(zero)? JAVA/Android

Question

I tried to develop the function in one way, but after multiple failed tests I created another way, but it keeps not generating what I'm searching for. I'm focusing only on 'Easy Division'.

The outputs appeared are like 7/2; 9/9; 9/8; 5/2;, and what I want is divisions like 9/9; 9/1; 6/3; 6/2;.

With remainder equaling 0 divisions. I hope you can help me, and sorry for my rusty English.

void generateDivisionOperation(String dificult){
    int n1, n2, aux;
    if(dificult == "Easy"){
        n1 = generateEasyNumber();
        do{
            aux = generateEasyNumber();
            if(remainderCalculatedBetween(n1,aux) != 0)
                aux = generateEasyNumber();
        }while (remainderCalculatedBetween(n1,aux) != 0);
                n2 = aux;
                textViewOperacaoN1.setText(String.valueOf(n1));
                textViewOperacaoN2.setText(String.valueOf(n2));
     }else{
        n1 = generateHardNumber();
        do{
            n2 = generateHardNumber();
        }while(n2 > n1 && n1%n2!=0);
            textViewOperationN1.setText(String.valueOf(n1));
            textViewOperationN2.setText(String.valueOf(n2));
    }
}

int generateEasyNumber(){
    int n1;
    int rangeEN = (9 - 1) + 1;
    n1 = (int) (Math.random() * rangeEN) + 1;
    return n1;
}

int generateHardNumber(){
    int n2;
    int rangeHN = (99 - 10) + 1;
    n2 = (int) (Math.random() * rangeHN) + 1;
    return n2;
}

int remainderCalculatedBetween(int n1, int n2){
    int remainder;
    remainder = n1 - n2*(int)(n1/n2);
    return remainder;

}

im trying to generate a division between two generated numbers wich the remainder of the result is zero — volkel, Feb 02 '17 at 17:46
`dificult == "Easy"` is the wrong way to compare strings. Use `dificult.equals("Easy")`. — shmosel, Feb 02 '17 at 18:01
You're correct shmose, but in that way i get the same outputs, i think the glitch is not there. Already changed it anyways — volkel, Feb 02 '17 at 18:15
Perhaps the part you DID NOT share with is not working right? Yea i'm taking about remainderCalculatedBetween() — Mehmet K, Feb 02 '17 at 19:09
its shared you just have to SCROLL DOWN the code, and yes its working — volkel, Feb 02 '17 at 19:37
`n1 - n2*(int)(n1/n2)` is just a convoluted way of calculating `n1 % n2`. — shmosel, Feb 03 '17 at 07:13

score 2 · Answer 1 · answered Feb 02 '17 at 17:38

2

Use a modulo sign % e.g. 10 % 3 is 1

answered Feb 02 '17 at 17:38

Mike

1,313
12
21

Already used that but it keeps appearing a division like 7/4. Thanks anyways. – volkel Feb 02 '17 at 17:57

score 0 · Answer 2 · answered Feb 02 '17 at 17:49

0

java provides '%' (modulus) operator to find the remainder. so the 'if' statement can be rewritten as:

if((n1%aux) != 0)

answered Feb 02 '17 at 17:49

Sneha

39
6

Already used that but it keeps appearing a division like 7/4. Thanks anyways. – volkel Feb 02 '17 at 17:58
if(dificult == "Easy"){ do{ n1 = generateEasyNumber(); aux = generateEasyNumber(); }while ((n1%aux) != 0); n2 = aux; textViewOperacaoN1.setText(String.valueOf(n1)); textViewOperacaoN2.setText(String.valueOf(n2)); } changing the code as above would help? – Sneha Feb 02 '17 at 18:45
i know the code you write make sense, but it seems the problem is not about the statement, i already tried all the answers here, the problem is not from those statements i guess – volkel Feb 02 '17 at 20:55

Mehmet K · Answer 3 · 2017-02-03T08:18:45.903

0

if(dificult.equals("Easy")){
    n1 = generateEasyNumber();
    do {
      aux = generateEasyNumber();
    } while (n1 % aux != 0);
    n2 = aux;
    textViewOperacaoN1.setText(String.valueOf(n1));
    textViewOperacaoN2.setText(String.valueOf(n2));
}

This works. I've tried it myself. Remove: if(remainderCalculatedBetween(n1,aux) != 0) aux = generateEasyNumber();

Replace == "Easy" with .equals("Easy")

and replace remainderCalculatedBetween(n1, aux) with n1 % aux;

I this does not work for you, perhaps you're not passing "Easy" to the function.

edited Feb 03 '17 at 08:18

answered Feb 02 '17 at 19:12

Mehmet K

2,805
1
23
35

Ok @howdoidothis thanks for the effort, tried your answer now, this still not showing what i look for. The glitch should be anything else and not this function. – volkel Feb 03 '17 at 18:30
But this IS the part you asked about. You said you're only focusing on "Easy" division, and this is the only part of code related to that. And my answer solves the 2 problems you have with that part of the code. If you havent debugged your code to know that the error generates from this function why are you asking for our help at that specific point. – Mehmet K Feb 06 '17 at 12:01

score 0 · Answer 4 · answered Feb 10 '17 at 22:26

0

Well the problem was in another point of the program, as @Mehmet Kologlu said that version is correct. Sorry for answering late. Already running without problems.

answered Feb 10 '17 at 22:26

volkel

1
1

How do I generate a division operation where its result will have remainder 0(zero)? JAVA/Android

4 Answers4