EntityFramework Core Fluent Model Builder Key and Property

Question

Ok so in entity framework 6 I would have had a key and property database generation in one statement:

modelBuilder.Entity<Function>()
                .HasKey(x => x.Id)
                .Property(x => x.Id)
                .HasDatabaseGeneratedOption(DatabaseGeneratedOption.None);

In entity framework core (7) this does not work:

modelBuilder.Entity<Function>()
                .HasKey(x => x.Id)
                .Property(x => x.Id)
                .ValueGeneratedNever();

Error: "'KeyBuilder' does not contain a definition for 'Property' and no extension method 'Property' accepting a first argument of type 'KeyBuilder'":

Does this have to be two separate statements as below or is there a way to have it in one like you could in EF6?

protected override void OnModelCreating(ModelBuilder modelBuilder)
{
    modelBuilder.Entity<Function>()
                    .HasKey(x => x.Id);

    modelBuilder.Entity<Function>()
                    .Property(x => x.Id)
                    .ValueGeneratedNever();
}

score 5 · Accepted Answer · answered Jan 27 '17 at 16:46

Yes, they are separate in EF Core.

The reason is because EF6 method allows you to specify the PK columns and nothing more, hence is returning EntityTypeConfiguration<TEntityType> (the same as the target obtained from Entity<...> call) and that's why you can continue fluently configuring the entity type.

However the EF Core method returns a different type called KeyBuilder which allows you to further configure the PK, like HasName for the relational constraint name, or specific database attributes like ForSqlServerHasName and ForSqlServerIsClustered etc.

EntityFramework Core Fluent Model Builder Key and Property

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