The short answer is :
if let navController = self.navigationController {
return navController.viewControllers[navController.viewControllers.count - 1]
// take care if count <= 1
else {
return self.parent
}
But is this what you really looking for ? What behavior are you trying to implement based on who is his parent ?
I don't have the answer to this question but you should make your code readable. Let me explain by an example :
let phonePage = storyboard.instantiateViewControllerWithIdentifier("phoneViewController") as! PhoneViewController
// Option 1
self.navigationController?.pushViewController(phonePage, animated: true)
phonePage.mode = PhonePageMode.list
// Option 2
self.presentViewController(phonePage.embedInNavController(), animated: true, completion: nil)
phonePage.mode = PhonePageMode.grid
// In your PhoneViewController class
switch self.mode {
case .list: // present as a list
case .grid: // present as a grid
}
is more readable than :
let phonePage = storyboard.instantiateViewControllerWithIdentifier("phoneViewController") as! PhoneViewController
// Option 1
self.navigationController?.pushViewController(phonePage, animated: true)
// Option 2
self.presentViewController(phonePage.embedInNavController(), animated: true, completion: nil)
// In your PhoneViewController class
guard let parent = self.parentViewController else { return }
if parent is ThisClassWhichWantsAList {
// present as list
} else if parent is ThisOtherClassWhichWantsAGrid {
// present as grid
}
If you want to use its parent as a condition to do things differently, you'd rather use an additional attribute. Your futur self will be thankful.