How do I handle this initializer?

Question

Create a class called Parent with a title property and write an init and deinit method for your class.

Write a subclass called Child.

My problem is putting this into the code (call super.init(title:) and pass on the title parameter.

class Parent {
    let title: String

    init(title: String){
        self.title = title
        print("\(title) is initialized")
    }

    deinit {
        print("\(title) is being deinitialized.")
    }
}

class Child: Parent {
    let subtitle: String
    init(subtitle: String){
        self.subtitle = subtitle
        // i'm supposed to call a super.init, how

        print("\(subtitle) is initialized")
    }

    deinit {
        print("\(subtitle) is being deinitialized.")
    }
}

vacawama · Accepted Answer · 2017-01-08T00:33:19.783

1

Make your initializer for your Child take both a title and a subtitle, and then call super.init(title: title) in your Child's initializer:

class Child: Parent {
    let subtitle: String
    init(title: String, subtitle: String){
        self.subtitle = subtitle
        super.init(title: title)

        print("\(subtitle) is initialized")
    }

    deinit {
        print("\(subtitle) is being deinitialized.")
    }
}

Then if you create a Child object and assign it to an Optional Child (i.e. Child?) you'll see both initialized messages:

var child: Child? = Child(title: "Star Wars: Episode VI", subtitle: "Return of the Jedi")

Star Wars: Episode VI is initialized
Return of the Jedi is initialized

and then if you assign nil to your variable you'll see both deinitialized messages:

child = nil

Return of the Jedi is being deinitialized.
Star Wars: Episode VI is being deinitialized.

edited Jan 08 '17 at 00:33

answered Jan 08 '17 at 00:14

vacawama

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Thank you so much. One more thing I forgot to put in "Create an optional var of type Child and assign a child object to it." – AllocSystems Jan 08 '17 at 00:16
1

`var child: Child? = Child(title: "some title", subtitle: "some subtitle")` – vacawama Jan 08 '17 at 00:18
1

Then if you follow that up with `child = nil`, you'll see both of your deinit messages. – vacawama Jan 08 '17 at 00:23

Schubert David Rodriguez · Answer 2 · 2017-01-08T03:23:19.370

0

I actually didn't try but I think it could work this way. Let me know if it works.

class Child: Parent {
    let subtitle: String

    override init(title: String, subtitle:String) {
        self.subtitle = subtitle
        super.init(title)
    }
}

edited Jan 08 '17 at 03:23

answered Jan 08 '17 at 00:19

Schubert David Rodriguez

54
2

Don't you have to specify a type for `title` and `string`? This code doesn't compile for me. – Benjamin Lowry Jan 08 '17 at 01:17
Yeah, you right, i think i doesn't compile it has to be defined both as string – Schubert David Rodriguez Jan 08 '17 at 03:23

How do I handle this initializer?

2 Answers2